pls do it urgent!!!!!!
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Now DE is parallel to BC.
So triangle ADE is similar to triangle ABC.
so AD/AB = DE/BC
that implies 5/9 = DE/BC
Now in triangles DEF and BFC,
angle BFC = angle DFE
angle FBC = angle FED
therefore triangle DFE is similar to triangle BFC.
So ar(DEF)/ar(BFC) = DE2 / BC2 = (5/9)2 = 25/81
Now DE is parallel to BC.
So triangle ADE is similar to triangle ABC.
so AD/AB = DE/BC
that implies 5/9 = DE/BC
Now in triangles DEF and BFC,
angle BFC = angle DFE
angle FBC = angle FED
therefore triangle DFE is similar to triangle BFC.
So ar(DEF)/ar(BFC) = DE2 / BC2 = (5/9)2 = 25/81
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