Question

pls do my help in Q4 (C and F) part of this question.of class-7th CBSE board​

Answer 1

(c)

• $\sf \frac{x}{2} + \frac{3}{4} = \frac{7}{8}$

• $\sf \frac{x}{2} = \frac{7}{8} - \frac{3}{4}$

• $\sf \frac{x}{2} = \frac{7}{8} - \frac{3 × 2}{4 × 2}$

• $\sf \frac{x}{2} = \frac{7 - 6}{8}$

• $\sf \frac{x}{2} = \frac{1}{8}$

• $\sf x = \frac{2}{8}$

• $\sf x = \frac{\cancel2^{\: \: 1}}{\cancel8_{ \: \: 4}}$

• $\sf \boxed{ x = \frac{1}{4}}$

(f)

• $\sf 2y + \frac{7}{2} = \frac{39}{2}$

• $\sf 2y = \frac{39}{2} - \frac{7}{2}$

• $\sf 2y = \frac{39 - 7}{2}$

• $\sf 2y = \frac{32}{2}$

• $\sf y = \frac{32}{2 × 2 }$

• $\sf y = \frac{\cancel{32}^{\: \: 8}}{\cancel4}$

• $\sf \boxed{y = 8}$

I hope it helps you ❤️✔️

Answer 2

jxisshixmxis!is i dont know