Pls do question 8 and 9
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Q-8
Step-by-step explanation:
GIVEN - QR = RT, QP = ST & <PQR = <RTS =70
∆PQR = ∆RST (BY SAS)
S - QR = RT ( given in fig.)
A - <PQR= <RST (angle given both 70°)
S - QP = ST (given in fig.)
Therefore, ∆ PQR = ∆RST
Hence proved..
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