Question

Pls do step by step and don't spam ​

Answer 1

Answer:

Step-by-step explanation:

in triangle ABM and triangle CBM

∠A=∠C           (GIVEN)

BM=BM          (COMMON)

∠B IS BISECTED BY BM

SO, 1/2∠B=∠B   (COMMON)

BY ASA TEST

BM IS PERPENDICULAR TO ∠B