Question

pls do the question with explanation.​

Answer 1

Step-by-step explanation:

SinQ/1+CosQ+1+CosQ/SinQ=4

(Sin^2Q)+ (1+CosQ)^2/(1+CosQ)(SinQ)=4

(Sin^2Q+Cos^2Q)+1+2CosQ/(1+CosQ)(SinQ)=4

2+2CosQ/(1+CosQ)(SinQ)=4

2(1+CosQ)/(1+CosQ)(SinQ)=4

2/SinQ=4

SinQ=8

Q=8/Sin

Answer 2

GIVEN :–

$\\ \bf \implies \dfrac{ \sin( \phi) }{1 + \cos( \phi) } + \dfrac{1 + \cos( \phi) }{ \sin( \phi) } = 4$

TO FIND :–

$\\ \implies \phi = ?$

SOLUTION :–

$\\ \bf \implies \dfrac{ \sin( \phi) }{1 + \cos( \phi) } + \dfrac{1 + \cos( \phi) }{ \sin( \phi) } = 4$

$\\ \bf \implies \dfrac{ \sin ^{2} ( \phi) + \{1 + \cos( \phi) \}^{2} }{ \{\sin( \phi) \}\{1 + \cos( \phi) \}}= 4$

$\\ \bf \implies \dfrac{ \sin ^{2} ( \phi) + 1 + \cos^{2} ( \phi) + 2 \cos( \phi) }{ \{\sin( \phi) \}\{1 + \cos( \phi) \}}= 4$

$\\ \bf \implies \dfrac{ \sin ^{2} ( \phi) + \cos^{2} ( \phi) + 1+ 2 \cos( \phi) }{ \{\sin( \phi) \}\{1 + \cos( \phi) \}}= 4$

$\\ \bf \implies \dfrac{1+ 1+ 2 \cos( \phi) }{ \{\sin( \phi) \}\{1 + \cos( \phi) \}}= 4$

$\\ \bf \implies \dfrac{2+ 2 \cos( \phi) }{ \{\sin( \phi) \}\{1 + \cos( \phi) \}}= 4$

$\\ \bf \implies \dfrac{2 \{1+ \cos( \phi) \}}{ \{\sin( \phi) \}\{1 + \cos( \phi) \}}= 4$

$\\ \bf \implies \dfrac{2}{ \sin( \phi) }= 4$

$\\ \bf \implies \sin( \phi) = \dfrac{2}{4}$

$\\ \bf \implies \sin( \phi) = \dfrac{1}{2}$

$\\ \bf \implies \sin( \phi) = \sin \left(\dfrac{\pi}{6} \right)$

$\\ \bf \implies \large{ \boxed{ \bf \phi =\dfrac{\pi}{6}}}$