pls do this I want the correct ans
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Kingimran43:
angle made at the center of the circle is double of the angle made at circumference of the circle. so answer is 80 degree
Answers
Answered by
4
★ Ello ★
here is your answer !!
given = < BOD = 160 °
< BCD = 1 / 2 < BOD
=> < BCD = 1 / 2 × 160 °
=> < BCD = 80 °
now ,
< BCD + < BAD = 180 ° { Cyclic Quadrilateral }
=> 80 ° + < BAD = 180 °
< BAD = 100 °
< X = 100
{ < X = < BAD = 100 }
hence , your answer is
★ 100 ° ★
hope it helps you dear !!
here is your answer !!
given = < BOD = 160 °
< BCD = 1 / 2 < BOD
=> < BCD = 1 / 2 × 160 °
=> < BCD = 80 °
now ,
< BCD + < BAD = 180 ° { Cyclic Quadrilateral }
=> 80 ° + < BAD = 180 °
< BAD = 100 °
< X = 100
{ < X = < BAD = 100 }
hence , your answer is
★ 100 ° ★
hope it helps you dear !!
Answered by
0
angle bcd =1/2 of 160= 80degree
so angle bad =180-80=100degree
so angle bad =180-80=100degree
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