Question

pls do this
I will mark you brainlist​

Answer 1

$\underline{\sf\ \ Given:-}$

• A triangle in which
• AB=AC
• AD= 90° (Altitude)

$\underline{\sf\ \ To\ Prove :-}\begin{cases}\sf{ i)\ \ \Delta ADB \cong \Delta ADC }\\ \sf{ ii)\ \ \angle B= \angle C}\\ \sf{iii)\ \ BD=DC}\end{cases}$

$\underline{\bullet{\mathscr{PROOF:-}}}$

$\dashrightarrow\sf\ \ In\ \Delta\ ADB\ and \ \Delta ADC\\ \\ \dashrightarrow\sf AB=AC\ \ \ \ \ \ \big\lgroup Given \big\rgroup\\ \\ \\ \dashrightarrow\sf \angle ADB= \angle ADC\ \ \ \ \ \ \big\lgroup Altitude\ 90^{\circ} \big\rgroup\\ \\ \\ \dashrightarrow\sf AD=AD\ \ \ \ \ \ \big\lgroup Common \big\rgroup\\ \\ \\ \sf \therefore\ \Delta ADB \cong \ \Delta ADC\ \ \big\lgroup By\ SAS\ criteria \big\rgroup$

$\bullet\sf\ \ \angle B= \angle C\ \ \ \ \ \ \big\lgroup C.P.C.T \big\rgroup\\ \\ \\ \bullet\sf\ \ BD=DC\ \ \ \ \ \ \big\lgroup C.P.C.T \big\rgroup$