pls do this problem.....
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Answered by
0
in firat case
distance=30km
speed = 40km/h
time = distance /speed
time = 30/40
time = 3/4h
..
in second case
distance = 50km
speed = 20km/h
time = distance /speed
time = 50/20
time =5/2h
...
total distance=30+50=80km
total time = 3/4+5/2= 3.25h
...
average speed = toatal distance /totaltime
average speed= 80/3.25
average speed =24.61km/h
distance=30km
speed = 40km/h
time = distance /speed
time = 30/40
time = 3/4h
..
in second case
distance = 50km
speed = 20km/h
time = distance /speed
time = 50/20
time =5/2h
...
total distance=30+50=80km
total time = 3/4+5/2= 3.25h
...
average speed = toatal distance /totaltime
average speed= 80/3.25
average speed =24.61km/h
Harshitasood:
u can write 24.6 approx
Answered by
1
Average speed = total distance / total time
=)) 30km+50km(t¹+t²)
.
[80km/(30km/40km+50km/20km)]
=))[80km/(3/4h+5/2h)]
[80/(3/4+10/4)h]
[80/13/4]
=80*4/13
=))320/13
=24.61....
=)) 30km+50km(t¹+t²)
.
[80km/(30km/40km+50km/20km)]
=))[80km/(3/4h+5/2h)]
[80/(3/4+10/4)h]
[80/13/4]
=80*4/13
=))320/13
=24.61....
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