Pls dolve this all please fast urgent
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HELLO MY DEAR FRIEND
1ST SOLUTION - LET US TAKE A,B AND C.
THE VALUE OF A = 60 DEGREES
THE VALUE OF B = 50 DEGREES
THE VALUE OF C = ?
HERE WE HAVE TO USE THE SUM OF TRIANGLE FORMULA
= THE SUM OF ALL SIDES OF A TRIANGLE = 180 DEGREES
= A + B + C = 180 DEGREES.
= 60 DEGREES + 50 DEGREES + C DEGREE = 180 DEGREES.
= 60 DEGREES + 50 DEGREES = 110 DEGREES.
= 180 DEGREES - 110 DEGREES = 70 DEGREES
THEREFORE, THE VALUE OF THE C = 70 DEGREES.
2 ND SOLUTION - THE VALUE OF THE 1ST ANGLE = 43 DEGREES.
THE VALUE OF THE 2ND ANGLE = 90 DEGREES
( THE VALUE OF 2ND ANGLE IS 90 DEGREES BECAUSE THE 2ND ANGLE IS RIGHT ANGLE. SO WE
CAN SAY THAT 2ND ANGLE = 90 DEGREES).
THE VALUE OF THE 3RD ANGLE = ?
LET US TAKE 1ST ANGLE = A
2ND ANGLE = B
3RD ANGLE = C
HERE WE HAVE TO USE THE SUM OF ALL SIDES OF A TRIANGLE FORMULA.
= THE SUM OF ALL SIDES OF A TRIANGLE = 180 DEGREES.
= A+B+C = 180 DEGREES
= 43 DEGREES + 90 DEGREES = 133 DEGREES
= 180 DEGREES - 133 DEGREES = 47 DEGREES
THEREFORE, THE C = 47 DEGREES.
3RD SOLUTION - LET US TAKE A, B , C
A =123 DEGREES
B =48 DEGREES
C = LET'S TAKE X DEGREE
SUM OF ALL SIDES OF A TRIANGLE = 180 DEGREES.
= A + B + C = 180 DEGREES
123 + 48 = 171
= 171 - 123 = 9 DEGREES
THEREFORE THE C = 9 DEGREES
5 TH SOLUTION - A = 73 DEGREES
B =65 DEGREES
D = ?
THE SUM OF ALL SIDES OF A TRIANGLE = 180 DEGREES
= A + B + D = 180 DEGREES
= 73 + 65 = 138 DEGREES
= 180 DEGREES - 138 DEGREES = 42 DEGREES
THE VALUE OF C = 42 DEGREES.
6TH SOLUTION - A = 23 DEGREES
B = 38 DEGREES
C =?
SUM OF ALL SIDE OF A TRIANGLE = 180
A + B + C =180
23 + 38 = 61 DEGREES
= 180 DEGREES - 61 DEGREES = 120
THEREFORE THE C = 120 DEGREES.
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I HOPE THIS WILL HELP'S U.....................*-*
1ST SOLUTION - LET US TAKE A,B AND C.
THE VALUE OF A = 60 DEGREES
THE VALUE OF B = 50 DEGREES
THE VALUE OF C = ?
HERE WE HAVE TO USE THE SUM OF TRIANGLE FORMULA
= THE SUM OF ALL SIDES OF A TRIANGLE = 180 DEGREES
= A + B + C = 180 DEGREES.
= 60 DEGREES + 50 DEGREES + C DEGREE = 180 DEGREES.
= 60 DEGREES + 50 DEGREES = 110 DEGREES.
= 180 DEGREES - 110 DEGREES = 70 DEGREES
THEREFORE, THE VALUE OF THE C = 70 DEGREES.
2 ND SOLUTION - THE VALUE OF THE 1ST ANGLE = 43 DEGREES.
THE VALUE OF THE 2ND ANGLE = 90 DEGREES
( THE VALUE OF 2ND ANGLE IS 90 DEGREES BECAUSE THE 2ND ANGLE IS RIGHT ANGLE. SO WE
CAN SAY THAT 2ND ANGLE = 90 DEGREES).
THE VALUE OF THE 3RD ANGLE = ?
LET US TAKE 1ST ANGLE = A
2ND ANGLE = B
3RD ANGLE = C
HERE WE HAVE TO USE THE SUM OF ALL SIDES OF A TRIANGLE FORMULA.
= THE SUM OF ALL SIDES OF A TRIANGLE = 180 DEGREES.
= A+B+C = 180 DEGREES
= 43 DEGREES + 90 DEGREES = 133 DEGREES
= 180 DEGREES - 133 DEGREES = 47 DEGREES
THEREFORE, THE C = 47 DEGREES.
3RD SOLUTION - LET US TAKE A, B , C
A =123 DEGREES
B =48 DEGREES
C = LET'S TAKE X DEGREE
SUM OF ALL SIDES OF A TRIANGLE = 180 DEGREES.
= A + B + C = 180 DEGREES
123 + 48 = 171
= 171 - 123 = 9 DEGREES
THEREFORE THE C = 9 DEGREES
5 TH SOLUTION - A = 73 DEGREES
B =65 DEGREES
D = ?
THE SUM OF ALL SIDES OF A TRIANGLE = 180 DEGREES
= A + B + D = 180 DEGREES
= 73 + 65 = 138 DEGREES
= 180 DEGREES - 138 DEGREES = 42 DEGREES
THE VALUE OF C = 42 DEGREES.
6TH SOLUTION - A = 23 DEGREES
B = 38 DEGREES
C =?
SUM OF ALL SIDE OF A TRIANGLE = 180
A + B + C =180
23 + 38 = 61 DEGREES
= 180 DEGREES - 61 DEGREES = 120
THEREFORE THE C = 120 DEGREES.
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I HOPE THIS WILL HELP'S U.....................*-*
Sarithik:
Tq
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