pls don't give me fake answers
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can you please give the angles
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1
Answer:
Take Triangle AOB
AO=5cm
BO=12cm
Angle O= 90°
Using Pythagorean Theorem
a²+b²=c²
5²+12²=c²
√25+144=c
√169=c
c=13cm
Take Triangle ABC
A=14cm
B=15cm
C=13cm
S=(a+b+c)/2
S= (14+15+13)/2
S= 42/2
=21
Using herons formula
√s(s-a)(s-b)(s-c)
√21×(21-14)(21-15)(21-13)
√21×7×6×8
√7056
=84 cm²
Therefore Area of the Triangle ABC=84cm²
Now find the Area of the Triangle AOC similarly by the above steps and substract it from the Area of the Triangle ABC to find the Area of the shaded part.
Hope it helps....✌
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