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Answers
Answer:
Step-by-step explanation:
area of the tin sheet = csa of the cylinder + csa of the frustrum
for cylinder:
radius=4cm
height=10cm
csa of cylinder:
=>2πrh
=>2π*4*10
=>80π
for frustrum:
height=10cm
radius1=9cm
radius2=4cm
csa of frustrum:
=>π(r1+r2)l
slant height=l
=>√[h²+(r1-r2)²]
=>√[(22-10²)+(9-4²)]
=>√[12²+5²] = √[144+25] = √(169)
=>l=13cm
CSA of frustrum :
=>π(r1+r2)l
=>π(9+4)13=169π
SO THE REQIURED TOTAL CSA IS :
=>80π+169π = 249π
=> 249*22/7 = 782.571cm²
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Answer:
Diameter of top of funnel =18 cm
Radius (R) = 9 cm
Diameter of cylindrical portion = 8 cm
radius r = 4 cm.
So,
Height of frustum = Total height - Height of cylindrical part
==> 22 - 10
==> 12 cm
and Slant Height, l = √{h^2 + (R - r)^2}
==> √{(12)^2 +(9 - 4)2
==> √144 + 25
==> √169
==> 13 cm
Now, CSA of frustum = πl (R + r)
==> 22/7 * 13 * 13
==> 531.14 cm^2
Height of cylinder, H = 10 cm
Now, CSA of cylinder = 2πrH
==> 2 * 22/7 * 4 * 10
==> 251.42
Area of tin required = CSA of frustum + CSA of cylinder
==> 531.14 + 251.42
==> 782.6 cm^2.
Hence, Area of tin sheet required = 782.6 cm^2.