Question

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Answer 1

$\huge\underline{\overline{\mid{\bold{\red{ANSWER-}}\mid}}}$

Velocity of man = 2 km/ h or 2 i ^

velocity of rain W. r. t man = 2 km / h or 2 J ^

we know

Vrm=Vr -Vm

2j. = vr -2 i

Vr= √ 2² +2²

(Vr= 2 √2. ) required ans

now direction

let β is the angle which velocity of rain makes with vertical

tanβ = Vm/Vrm

= 2 /2=1

β = 45°

Answer 2

☞ANSWER:

v_Rv

R

= 2√2 kmph along South-east(45° with east).

☞ASSUMPTIONS:

v_mv

m

= Velocity of man.

v_rv

r

= velocity of rain with respect to man.

v_Rv

R

= original velocity of rain.

☞GIVEN:

v_mv

m

= 2 kmph

v_rv

r

= 2 kmph

☞TO FIND:

v_Rv

R

= ??

☞EXPLANATION:

v_Rv

R

will be the vector sum of v_mv

m

and v_rv

r

.

$$\begin{lgathered}v_R = \sqrt{ {v_r}^{2} +{v_m}^{2} } \\ v_R = \sqrt{ {2}^{2} +{2}^{2} } \\ v_R = \sqrt{ 8} \\ v_R = 2 \sqrt{ 2} \:kmph\end{lgathered}$$

THE ORIGINAL VELOCITY WILL MAKE 45° WITH BOTH THE VELOCITY OF MAN AND VELOCITY OF RAIN WITH RESPECT TO MAN.

Hence option A is correct.