pls explain...............
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given triangles ABC and DBC are on the same base BC. consider triangles ABC and DBC
A= D=90
GIVEN
angle AEB = angle DEC (Vertically opposite angles are equal)
Hence triangle ABC similar to triangle DBC (AA similarity theorem.) so
lastly
see the figure
given triangles ABC and DBC are on the same base BC. consider triangles ABC and DBC
A= D=90
GIVEN
angle AEB = angle DEC (Vertically opposite angles are equal)
Hence triangle ABC similar to triangle DBC (AA similarity theorem.) so
lastly
see the figure
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