Question

Pls explain briefly coz I have test in weeks
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Answer 1

Answer:

It's an easy one .

Step-by-step explanation:

You need to know that x to the power of 0 is 1 . So you will get the denominator as well as numerator equal .

Answer 2

Answer:

$\frac{x ^{m+n} X x^{n+l} X x^{l+m}}{x^{m} X x^{n} X x^{l} } = 1$

$x^{m+n} X x^{n+l} X x^{l+m} = x^{m+n+n+l+l+m} =x^{2(l+m+n)}$

$(x^{m} X x^{n} X x^{l})^{2} =x^{(m+n+l)^{2}} =x^{2}^{(m+n+l)}$

$LHS = \frac{ x^{m+n} X x^{n+l} Xx^{l+n} }{ (x^{m} X x^{n} X x^{l} )^{2} } \\ =\frac{x^{2(m+l+n)} }{x^{2 (m+l+n)}}$

$= 1 = RHS \\ hence proved$

Note :$X$= multiplication sign

Step-by-step explanation:

Best of luck for your exam buddy/bro