Question

pls explain in detail. ​

Answer 1

Heya mate !!!

Answer refers to the attachment .✔

Answer 2

$\bf{\blue{\bigstar}}$ Answer :

$\bold{x=\frac{1}{2-\frac{1}{2-\frac{1}{2-x} } } }\\\\\implies \bold{x=\frac{1}{2-\frac{1}{\frac{2(2-x)-1}{2-x} } } }\\\\\implies \bold{x=\frac{1}{2-\frac{(2-x)}{3-2x} } }\\\\\implies \bold{x=\frac{3-2x}{6-4x-2+x} }\\\\\implies \bold{x=\frac{3-2x}{4-3x} }\\\\\implies \bold{4x-3x^2=3-2x}\\\\\implies \bold{3x^2-6x+3=0}\\\\\implies \bold{x^2-2x+1=0}\\\\\implies \bold{(x-1)^2=0}\\\\\implies \bold{\bf{\red{x=1}}}$