Question

pls explain in full steps properly pls I have exams tomorrow pls help​

Answer 1

Step-by-step explanation:

In ∆ ADB and ∆ ADC

Seg AD = Seg AD ( Common Seg)

Angle BAD = Angle CAD ( AD is angle Bisector )

Angle ADB= Angle ADC ( Each of 90°)

∆ ABD congruent to ∆ ACD ( by SAS Test)

Thus, AB = AC ( by CSCT)

Hence, ABC is an isosceles ∆.