Question

pls explain me clearly and dont skip any steps plsss​

Answer 1

Step-by-step explanation:

Given

• Radius of Penholder (r)= 3 cm
• Height of Penholder (h)= 10.5 cm

Cardboard required for 1 competitor= C.S.A. of one penholder+area of base

$2\pi \times r \times h + \pi \times r {}^{2} \\ = (2 \times \frac{22}{7} \times 3 \times 10.5) + ( \frac{22}{7} \times 3 {}^{2} ) \\ = (198 + \frac{198}{7}) \\ = \frac{1584}{7} cm {}^{2}$

.°. Cardboard required for 35 competitors

$( \frac{1584}{7} \times 35) = 7920 \: cm {}^{2}$

Hence, 7920 cm² of cardboard was required for to be bought for 35 competitors.

Answer 2

Answer:

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