Question

pls explain properly​

Answer 1

Answer : The answer is (1) option.

First resolve the weight of block into two components...

Mg sin 30° along the incline

Mg cos30° as shown in the above photo

Then write the pseudo force on the block (Ma)

Then resolve the pseudo force into two Components.

As we know the block doesn't move

Equate the forces that are acting along the incline

i.e Mg Sin30° = Ma cos 30°

Cancel mass on both sides ,then we get [a = g Tan30°]

Then we get first option..

Please support this Answer it took me a while to write a simple solution..Thank you!!