Math, asked by sonybhujelpd6by4, 11 months ago

Pls explain the above questions

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Answered by ishitamogha21
1
x²-2x-8

by middle term splitting,

x²+2x-4x-8

x(x+2)-4(x+2)

(x+2)(x-4)=0

x-2=0

x=2

and,

x+4=0

x=-4

so,zeroes are -2,4

now, verification,

x²-2x-8

where, a=1, b=-2, c=-8

sum of zeroes=-b/a

-2+4=-(-2)/1

2=2

now,

product of zeroes=c/a

-2×4=-8/1

-8=-8

hence, verified.

hope this answer will help you.

sonybhujelpd6by4: can I write.. either (x-4)=0. or (x+2)=0
ishitamogha21: yaa u can write
sonybhujelpd6by4: thank u
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