pls explain this question
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The ball reaches the bottom losing 20% of the its velocity with which it hits the glycerin surface. Let 'a' be the deceleration of the ball in glycerin and x be the height of the glycerin surface from bottom. So, average velocity of fall is = 10.5/2 = 5.25 m/s or 5.3 m/s. Aakash EduTech Pvt.
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