Question

pls explain with steps ​

Answer 1

Answer:

Given:-

Distance (s1) = 150m

Distance (s2) = 100m

Time = 2sec

To find:-

Distance after 2 sec

For first object

S = ut+1/2at^2

= 0×2+1/2×10×4

= 20m.

Distance after 2 sec will be 150 - 20 = 130m.

For second object

S = ut+1/2at^2

= 0×2+1/2×10×4

= 20m.

Distance after 2 sec will be 100 - 20 = 80m.