Question

pls factorise these ​

Answer 1

Step-by-step explanation:

$1)216 {a}^{3} - 125 \\ = {(6a)}^{3} - {(5)}^{3} \\ = (6a - 5)(36 {a}^{2} + 25 + 30a) \\ \\ 2) {(3x + 4y)}^{3} + {(3x - 4y)}^{3} \\ = (3x + 4y + 3x - 4y)( {(3x + 4y)}^{2} + {(3x - 4y)}^{2} - (3x + 4y)(3x - 4y)) \\ = 6x(9 {x}^{2} + 16 {y}^{2} )$

Hope it helps maTe

for this you need to remember the identities.......

Answer 2

Answer:

Hey bro above is the step by step explanation of your question.