Question

Pls factorise X^3 -8​

Answer 1

Hope it is helpful.......

Answer 2

Step-by-step explanation:

${x}^{3} - 8 = {x}^{3} - {2}^{3}$

we know that

${a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )$

$a = x \: \: \: and \: \: \: b = 2$

$(x - 2)( {x}^{2} + 2x + 2^{2})$

$= (x - 2)( {x}^{2} + 2x + 4)$

this is ur answer pls mark me the brainilist