Question

pls fast evalute trigonometry que.​

Answer 1

Step-by-step explanation:

sec62°/cosec28°

sec(90°-28°)/cosec28°

cosec28°/cosec28°

1

sec(90°-ø) = cosecø

Answer 2

Answer:

$\frac{ \sec(62) }{ \csc(28 ) } \\ \\ = > \frac{ \sec(62) }{ \sec(90 - 28) } \\ = > \frac{ \sec(62) }{ \sec(62) } \\ = > 1$