Question

pls fast in step by step​

Answer 1

Answer:

Step-by-step explanation:

Now we are given that each student that participates in mass drill requires 225m of ribbon.

Let us first simplify the above fraction. Now we know that 225m is nothing but 2+25

Hence we can also write it as 21+25 Since 21=2 .

Now taking LCM of 1 and 5 we get

225=10+25=125

Hence we get 225m=125m .

Hence each student requires 125m length of ribbon..

Now let us consider there are x number of students in drill.

Now if each student requires 125m length of ribbon,

Then the x number of students will require (125×x)m length of ribbon.

Hence we get x number of students requiring (125×x)m length of ribbon.

Now we are given that the total length ribbon is 240m.

Hence we get the equation

(125×x)=240

Now multiplying the above equation by 5 we get

12x=240×5

Now dividing the above equation by 12 we get

x=20×5⇒x=100

Hence we get total number of students who participated in the drill is 100.

Answer 2

Answer:

100 participants

Step-by-step explanation:

ribbon req. by single participant = 2.4m

Total length of ribbon = 240m

total no. of participants, x

x = (total length) / req. length by a participant

x = 240 / 2.4

x = 100