Question

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question 28

Answer 1

Answer:

Step-by-step explanation:

Let AD= 5m (the Flag staff)

Let DB=h (tower)

Let BC=x (Distance between the point and the tower)

Now, in ΔABC,

Tan 60= AB/BC

√3=5+h/x

h=√3x-5     ---(i)

Now in ΔDBC,

Tan 30= DB/BC

1/√3=h/x

h=x/√3     ------(ii)

From (i) and (ii)

x/√3=√3x-5

x=√3(√3x-5)

x=3x-5√3

2x=5×1.732

x=5×1.732/2

x=4.33=BC

Putting the value of x in (ii)

4.33/1.732=h

=2.5

Height of tower = 2.5

Distance=4.33

Answer 2

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