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the angle of elevation of a cloud from the point p 60 m above the surface of a lake is 30 and the angle of depression of the reflection of the cloud in the lake at p is 60 find the height of the cloud from the surface of the lake
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Let AO=H
CD=OB=60m
A'B=AB=(60+H)m
In triangke AOD,
tan30'=AO/OD=H/OD
H=OD/√3
OD=√3 H
Now, in triangle A'OD,
tan60'=OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
=(120+H)/√3 H
=>120+H=3H
2H=120
H=60m
Thus, height of the cloud above the lake = AB+A'B
=(60+60)
= 120m
<marquee> I hope u like it
CD=OB=60m
A'B=AB=(60+H)m
In triangke AOD,
tan30'=AO/OD=H/OD
H=OD/√3
OD=√3 H
Now, in triangle A'OD,
tan60'=OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
=(120+H)/√3 H
=>120+H=3H
2H=120
H=60m
Thus, height of the cloud above the lake = AB+A'B
=(60+60)
= 120m
<marquee> I hope u like it
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I have done it with respect to the question in the pic where CD Is 100 and not 60....
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nilabm2003:
what's wid the dots bro
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