pls find 1/√2+√3 It's urgent
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1/√2+ √3 is to be multiplied by the conjugate of the denominator ie √2 - √3 to both numerator and the denominator
=> (√2 - √3)/ (√2 + √3)(√2 - √3)
=> (√2 - √3)/2 - 3
=> (√2 - √3 )/-1
=> -(√2 - √3 )
,=> √3 - √2
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