Question

Pls find 71 question

Answer 1

Solution

volume of the sphere of radius 3.5 cm

$= (\frac{4}{3} \times \frac{22}{7} \times 3.5 {}^{3} )cm {}^{3} \\ = \frac{539}{3} cm {}^{3}$

now mass of the sphere is

=volume×density

$=( \frac{539}{3} \times 2)gm \\ = \frac{1078}{3} gm$

now from the second law of motion

$f = ma = (\frac{1078}{3} \times 1.5)dyne = 539 \: dyne$