Pls find in the given figure... 1)acd 2)aed
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Answer:
∠ACD=85o
∠AED=115o
Step-by-step explanation:
According to Exterior Angle Property in △ABC
∠ACD=∠CAB+∠CBA=35 +50 =85
Applying same property
∠AED=∠ACD+∠ECD=85 +30 =115
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