Question

pls find it........​

Answer 1

Answer:

please send the clear image

Answer 2

Answer:

here

angle PBA = 60°

and angle ACQ = 70°

angle OCA = 90- angle ACQ = 90 - 70 = 20°

angle OCA = 20°

angle OBA = 90 - angle PBA = 90 - 60° = 30°

angle OBA = 30°

in ∆ AOB

OB = OA = radii

so angle OBA = angle OAB = 30°

angles opposite to the equal sides are equal

in ∆AOC

OC = OA = radii

so angle OCA = angle OAC = 20°

C = 20°angles opposite to the equal sides are equal

here angle BAC = angle OAB + angle OAC

angle BAC = 30° + 20°

angle BAC = 50°

we know

angle BOC = 2 x angle BAC

angle BOC = 100°

as TBOC is cyclic quadrilateral

so the sum of opposite angle is 180°

therefore angle BOC + angle BTC = 180°

angle BTC = 180 - 100 = 80°

angle BTC = 80°

hope this will help you