Question

pls find the answer it's very urgent .. I don't need unwanted answers...​

Answer 1

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Given: ABC is a triangle, DE || BC, AD = x, DB = x - 2, AE = x + 2 and EC = x - 1.

To find: x

In △ABC, we have

DE || BC

Therefore [By Thale's theorem]

AD/DB = AE/EC

AD × EC × = AE × DB

x(x-1) = (x-2)(x+2)

x2 - x = x2 - 4

x = 4

Answer 2

Answer:

Given: ABC is a triangle, DE || BC, AD = x, DB = x - 2, AE = x + 2 and EC = x -

To find: x

In △ABC, we have

DE || BC

Therefore [By Thale's theorem]

AD/DB = AE/EC

AD × EC × = AE × DB

x(x-1) = (x-2)(x+2)

x2 - x = x2 - 4

x = 4

Step-by-step explanation: