Question

pls find the answer pls help

Answer 1

let the shortest side be x
then the third side equals to x+1
then the hypotenuse =x-1
x+x-1=x+1
2x-1=x+1
2x-x=1+1
x=2m
x+1=2+1=3m
x-1=2-1=1m

Answer 2

let the shortest side be x then
a/q the hypotenuse will be..2x-1

third side=x+1....now
${(2x - 1)}^{2} = {x}^{2} + {(x + 1) }^{2} \\ 4 {x}^{2} + 1 - 4x = 2 {x}^{2} + 1 + 2x \\ 2 {x}^{2} - 6x = 0 \\ 2x(x - 3) =0 \\ x = 0 \\ x = 3$