Question

Pls find the hybridisation of N3-, NO3-, NO2- using the hyb formula

Answer 1

N3-   NO3- NO2-   is SP2 hybridised

Answer 2

Hybridization calculation of $N_3^-, NO_3^-$ and $NO_2^-$

• The formula used for calculation of hybridization is as follows:

$X = \frac{1}{2}[V+M-C+A]$

Where,

V - Number of valence electrons on the central atom.

M - Number of monovalent groups

C - Number of positive charges

A - Number of negative charges

• Calculation of hybridization of given ions is as follows:

(i)$N_3^-$

In $N_3^-$,

V = 5

M = 0

C = 0

A = 3

∴ $X = \frac{1}{2}[V+M-C+A]$

$X = \frac{1}{2}[5+0-0+3]$

$X = \frac{1}{2}\times 8$

$X = \frac{8}{2} =4$

• Thus the hybridization of $N_3^-$ is $sp^3$.

(ii) $NO_3^-$

V = 5

M = 0

C = 0

A = 1

∴ $X = \frac{1}{2}[V+M-C+A]$

$X = \frac{1}{2}[5+0-0+1]$

$X = \frac{1}{2}\times 6$

$X = \frac{6}{2} =3$

• Thus the hybridization of $NO_3^-$ is $sp^2$

(iii) $NO_2^-$

V = 5

M = 0

C = 0

A = 1

∴ $X = \frac{1}{2}[V+M-C+A]$

$X = \frac{1}{2}[5+0-0+1]$

$X = \frac{1}{2}\times 6$

$X = \frac{6}{2} =3$

• Thus the hybridization of $NO_2^-$ is $sp^2$

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