pls find the solution?????
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3.Let put p(X)=5x-4x^2+3
putting X=-1
p(-1)=5×(-1)-4×(-1)^2+3
p(-1)=-5-4+3
=-6
Let put p(X)=5x-4x^2+3
putting X=2
p(2)=5×(2)-4×(2)^2+3
p(2)=10-16+3
=-3
4.finding remainder when 4x^3+3x^2-4x+k is divided by x-1
Let divisor =0
x-1=0
X=1
let p(X)=4x^3+3x^2-4x+k
putting X=1
p(1)=4×(1)^3+3×(1)^2-4×(1)+k
p(1)=4+3-4+k
p(1)=3+k
Thus ,remainder =3+k
since x-1 is a factor of 4x^3+3x^2-4x+k
Remainder is zero,
since,3+k=0
k=-3
Thus,k=-3
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