Question

pls find the solution.

Answer 1

=log 5^2 to the base 2^4
=2/4log5 to the base 2
k=1/2

Answer 2

$\sf{GIVEN:-}$

$\sf{\log_{16}25 = k\log_25}$

$\sf{\log_{2^4}5^2 = k\log_25}$

$\sf{\frac{2}{4} \log_25 = k\log_25}$

$\to\to\to\to\to\to\therefore\boxed{\sf{[ \log_{y^n}(x^m) = \frac{m}{n}\log_yx]}}$

$\sf{\frac{2}{4} = k}$

$\sf{\frac{1}{2} = k}$