pls find the unknown angle
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in triangle BCD angle CBD And CDB ARE EQUAL AS TRIANGLE BCD IS ISOSCELES TRIANGLE
THEREFORE
angle CBD + ANGLE CDB + 90 = 180
ANGLE CBD + ANGLE CDB = 90 ( as angle CBD= ANGLE CDB )
2(ANGLE CDB ) = 90
ANGLE CDB = 45
THEREFORE
angle CBD + ANGLE CDB + 90 = 180
ANGLE CBD + ANGLE CDB = 90 ( as angle CBD= ANGLE CDB )
2(ANGLE CDB ) = 90
ANGLE CDB = 45
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bhumi8990:
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