Question

pls find the zeros of 4S²-4S+1 and verify. urgent!!!!

Answer 1

hi friend
here the quadratic equation is 4s²-4s+1_______________________(1)
By using factorization method
4s²-4s+1=0
4s²-2s-2s+1=0
2s(2s-1)-1(2s-1)=0
(2s-1)(2s-1)=0
either (2s-1) is its zero or (2s-1) = 0
so the zeros are s=$\frac{1}{2}$ ,s=$\frac{1}{2}$
put the value of s in eq (1)
we got $4 X \frac{1}{4} -4X \frac{1}{2} +1 = 1 - 2+1=2-2=0$
hence the factor lead equation becomes zero so,
hence verified
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Answer 2

you can verify the zeros by substituting the value of "s" in the equation and you will get zero