Question

PLS FIND VALUES OF A ,B , C

Answer 1

Step-by-step explanation:

Hi dear mate... Here you go

6/3√2-2√3=a√2-b√3

First, we need to rationalize.

6*3√2+2√3/3√2-2√3*3√2+2√3

6(3√2+2√3)/18-12

6(3√2+2√3)/6

6 gets cancelled.

3√2+2√3 = a√2-b√3

√2 and √3 gets cancelled.

a=3

-b=2 therefore b=2

Answer 2

Answer:

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