Question

pls find volume and CSA for this​

Answer 1

Answer:

Given,

diameter=6cm

radius=3cm

ht of cone=4cm

ht of cylinder=25-4cm=21cm

now

volume=v of cone+v of cylinder

volume=1÷3×22÷7×3^2+22÷7×3^2×21

=631.71

Answer 2

GIVEN :

• CYLINDER IS SUMMOUNTED BY A CONE
• DIAMETER OF BASE OF CYLINDER IS 6 cm
• HEIGHT OF CONE = 4 cm
• TOTAL HEIGHT OF SOLID = 25 cm
• π = 22/7

TO FIND :

1. VOLUME OF SOLID
2. CURVED SURFACE AREA (CSA) OF SOLID

SOLUTION :

TOTAL HEIGHT OF SOLID = HEIGHT OF CONE + HEIGHT OF CYLINDER

=> 25 = 4 + HEIGHT OF CYLINDER

=> HEIGHT OF CYLINDER = 21 cm

RADIUS = DIAMETER/ 2 = 6/2 = 3 cm

RADIUS OF CYLINDER = RADIUS OF CONE

HEIGHT OF CONE = 4 cm

RADIUS OF CONE = 3 cm

SLANT HEIGHT OF A CONE BE l

IN A CONE ,

$l {}^{2} = {r}^{2} + {h}^{2} \\ \\ = > {l}^{2} = 9 + 16 \\ \\ = > {l}^{2} = 25 \\ \\ = > l = 5 \: cm$

1 ] VOLUME OF SOLID = VOLUME OF CONE + VOLUME OF CYLINDER

$= > volume \: of \: solid = \frac{\pi {r}^{2} h}{3} + \pi {r}^{2} h \\ \\ = > volume \: of \: solid = \\ \\ \frac{22 \times9 \times 4 }{3 \times 7} + \frac{22}{7} \times 9 \times 21 \\ \\ = 37.7 + 594 = 631.7cm {}^{3}$

2 ] CSA OF SOLID = CSA OF CONE + CSA OF CYLINDER

$= > csa \: of \: solid \: = \pi rl + 2\pi rh \\ \\ = (\pi \times 3 \times 5 )+ (\pi \times 2 \times 3 \times 21) \\ \\ = 15\pi + 126\pi \\ \\ = \pi(141) = 44 3 .1 \: cm {}^{2}$

∴ VOLUME OF SOLID = 631.7 cm³ AND CSA OF SOLID = 443.1 cm²

HOPE IT HELPS !!!!