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Radius of outer track = (Outer Circumference) / 2π = 440 * 7 / (2 * 22) = 70m
Radius of inner track = (Inner Circumference) / 2π = 220 * 7 / (2 * 22) = 35m
Width = Outer Radius - Inner Radius = 35m
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Answered by
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Hey mate... Here's your answer
Given:
We know that,
Circumference of a circle=2πr units
Inner circumference of the track=220m
2πr=220
r=220×7/22 × 1/2
(Inner radius)r=35m
Outer circumference of the track=440m
2πR=440
R=440 × 7/22 × 1/2
(Outer radius)R=70m
Width of the track =. Outer radius - Inner radius
=70 - 35
=35m
Therefore width of the track = 35 m
Hope it helps you
pls mark it as brainliest
Given:
We know that,
Circumference of a circle=2πr units
Inner circumference of the track=220m
2πr=220
r=220×7/22 × 1/2
(Inner radius)r=35m
Outer circumference of the track=440m
2πR=440
R=440 × 7/22 × 1/2
(Outer radius)R=70m
Width of the track =. Outer radius - Inner radius
=70 - 35
=35m
Therefore width of the track = 35 m
Hope it helps you
pls mark it as brainliest
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