Question

pls find x in this equation , answer correctly with formula and i will mark as brainliest but pls no spam.

Answer 1

Answer:

$( { \frac{3}{4} })^{(x + 1)} \times ({ \frac{3}{4} })^{2x} = ({ \frac{3}{4} })^{ - 4x + 8}$

$( { \frac{3}{4} })^{(x + 1 + 2x)} = ({ \frac{3}{4} })^{ - 4x + 8}$

$( { \frac{3}{4} })^{3x + 1} = ({ \frac{3}{4} })^{ - 4x + 8}$

$comparing \: the \: powers$

$3x + 1 = - 4x + 8$

$7x = 7$

$x = \frac{7}{7}$

$x = 1$