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Find the value of a for which x-a is a factor of the polynomial x5-a³x²+2x+a-3
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Answered by
1
a=1 is the answer of your question that is for a=1 (x-a) is a factor of p(x).
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In question, the first term is 5a or a^5
Answered by
2
okay, so first of all we gonna find zero of x-a
Therefore, x= a
We will substitute a in the poly.
p(a)- 5(a)-(a)³(a)²+2(a)+a-3
5a-a^5+2a+a-3
5a+2a+a-a^5-3
8a-a^5-3
.
since the remainder ain't zero , x-1 isn't a factor of p(a)
Therefore, x= a
We will substitute a in the poly.
p(a)- 5(a)-(a)³(a)²+2(a)+a-3
5a-a^5+2a+a-3
5a+2a+a-a^5-3
8a-a^5-3
.
since the remainder ain't zero , x-1 isn't a factor of p(a)
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