Question

pls friends do all sums...​

Answer 1

Answer:

b'

(i)1440o

(2n−4) right angles = 1440o

(2n−4)×90=1440

2n−4=16

2n=20

n=10 sides

(ii)1800o

(2n−4) right angles = 1800o

(2n−4)×90=1800

2n−4=20

2n=24

n=12 sides

(iii)540o

(2n−4) right angles = 540o

(2n−4)×90=540

2n−4=6

2n=10

n=5 sides

'

regular polygon have sides = 4 

=178

and other question is not visible soo I hope it helps you