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4×12=48
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AD=
9
2
+9
2
=
81+81
=
162
=9
2
cm
∴ Area of shaded region
=Ar(semi−circle)+Ar(rectangle)−ar(ΔAED)
=
2
πr
2
+l×B−
2
1
×b×h
=
2
3.14×
2
9
×
2
9
+12×9
2
−
2
1
×9×9=63.58+152.28−40.5
=175.36cm
2
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