Question

Pls give a full explanation

Answer 1

Answer:

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Step-by-step explanation:

2S=5+4+3 ⇒ S=6

Area of ΔABC

=s(s−a)(s−b)(s−c)

=15(15−9)(15−8)(15−13)=6(1)(2)(3)=36=6

⇒For area of ΔADC, 

⇒2S=5+4+5 

⇒ S=7cm

⇒Area of ΔADC

=7(7−5)(7−5)(7−4)=7×2×2×3

=221=9.16m2

⇒Area of quad ABCD= Area of (△ABC+△ADC)

=6+9.16

=15.16  cm2≈15.2  cm2