Math, asked by kshitijanand, 1 year ago

pls give ans of above question.​

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Answers

Answered by clockkeeper
1

( {a}^{ \frac{1}{8} }  +  {a}^{ \frac{ - 1}{8} } )( {a}^{ \frac{1}{8} }  -  {a}^{ \frac{ - 1}{8} } )( {a}^{ \frac{1}{4} }  +  {a}^{ \frac{ - 1}{4} } )( {a}^{ \frac{1}{2} }  +  {a}^{  \frac{ - 1}{2} } ) \\  = ( {a}^{ \frac{1}{4} }  -  {a}^{ \frac{ - 1}{4} } )( {a}^{ \frac{1}{4} }  +  {a}^{ \frac{ - 1}{4} } )( {a}^{ \frac{1}{2} }  +  {a}^{ \frac{ - 1}{2} } ) \\  = ( {a}^{ \frac{1}{2} }  -  {a}^{ - \frac{ - 1}{2} } )( {a}^{ \frac{1}{2} }  +  {a}^{ \frac{ - 1}{2} } ) \\  = ( {a}^{1}  -  {a}^{ - 1} ) \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: (using \: property \: (x - y)(x + y) =  {x}^{2}  -  {y}^{2} ) \\  = a -  \frac{1}{a}

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