Question

pls give ans step by step​

Answer 1

Answer:

ANSWER

The 12Ω and 6Ω resistors are in parallel, so their equivalent resistance is R

1

=12×6/(12+6)=4Ω.

The 7Ω and 5Ω resistors are in series, so their equivalent resistance is R

2

=7+5=12Ω.

The R

1

=4Ω and R

2

=12Ω are in parallel, so their equivalent resistance is R

3

=12×4/(12+4)=3Ω

Now this R

3

=3Ω and 7Ω are in series, so the equivalent resistance is 7+3=10Ω

So the equivalent resistance of circuit is 10Ω