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Factorise 8x^3-1/27y^3
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Answer:
trying to factor as a Difference of Cubes:
Factoring: 216x3 - y3
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0+b3 =
a3+b3
Check : 216 is the cube of 6
hence factorising we gwt
(6x-y).(36x^2+6xy+y^2)
finally we get
(6x - y) • (36x2 + 6xy + y2)/27
Step-by-step explanation:
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