Question

pls give answer don't give incorrect answer (std 11) sum​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

L.C.M=105(2x^2-x-1)(2x^2-7x+3)L.C.M=105(2x

2

−x−1)(2x

2

−7x+3)

Step-by-step explanation:

Concept used:

L.C.M of the given two polynomial is a polynomial of least degree which divides the given two polynomial exactly.

L.C.M of the given polynomial is found by factorization maethod.

15(2x^2-x-1)15(2x

2

−x−1)

=3*5(2x^2-2x+x-1)=3∗5(2x

2

−2x+x−1)

=3*5[2x(x-1)+1(x-1)]=3∗5[2x(x−1)+1(x−1)]

=3*5(2x+1)(x-1)=3∗5(2x+1)(x−1)

35(2x^2-7x+3)35(2x

2

−7x+3)

=5*7[2x^2-6x-x+3]=5∗7[2x

2

−6x−x+3]

=5*7[2x(x-3)-1(x-3)]=5∗7[2x(x−3)−1(x−3)]

=5*7(2x-1)(x-3)=5∗7(2x−1)(x−3)

L.C.M=3*5*7*(2x+1)(x-1)(2x-1)(x-3)L.C.M=3∗5∗7∗(2x+1)(x−1)(2x−1)(x−3)

L.C.M=105(2x^2-x-1)(2x^2-7x+3)L.C.M=105(2x

2

−x−1)(2x

2

−7x+3)