pls give answer don't give incorrect answer (std 11) sum
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Step-by-step explanation:
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Answer:
L.C.M=105(2x^2-x-1)(2x^2-7x+3)L.C.M=105(2x
2
−x−1)(2x
2
−7x+3)
Step-by-step explanation:
Concept used:
L.C.M of the given two polynomial is a polynomial of least degree which divides the given two polynomial exactly.
L.C.M of the given polynomial is found by factorization maethod.
15(2x^2-x-1)15(2x
2
−x−1)
=3*5(2x^2-2x+x-1)=3∗5(2x
2
−2x+x−1)
=3*5[2x(x-1)+1(x-1)]=3∗5[2x(x−1)+1(x−1)]
=3*5(2x+1)(x-1)=3∗5(2x+1)(x−1)
35(2x^2-7x+3)35(2x
2
−7x+3)
=5*7[2x^2-6x-x+3]=5∗7[2x
2
−6x−x+3]
=5*7[2x(x-3)-1(x-3)]=5∗7[2x(x−3)−1(x−3)]
=5*7(2x-1)(x-3)=5∗7(2x−1)(x−3)
L.C.M=3*5*7*(2x+1)(x-1)(2x-1)(x-3)L.C.M=3∗5∗7∗(2x+1)(x−1)(2x−1)(x−3)
L.C.M=105(2x^2-x-1)(2x^2-7x+3)L.C.M=105(2x
2
−x−1)(2x
2
−7x+3)
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